Droo rotational speed is 158m/s at the equater
Droo's radius is 1274200
Droo's circumsrance would be 2×pi×r so it is 8006034.718
I take the circumsrance ÷ 360 to find out how long 1 degree on Droo would be and got 22238.98533 m.
I than took 158/22238.98533 to find the angular velocity which I got 0.0071 degrees/second
Am I correct?
Droo fact sheet.
Orbit Radius: 14 959 800 km
Apoapsis: 15 199 159 137 m
Periapsis: 14 720 445 463 m
Eccentricity: 0.016
Inclination: 0°
Orbital Period: 4 992 992.1 s
Physical Characteristics
Radius: 1 274 200 m
Mass: 2.38 X 1023kg
Rotation Period: 50 400 s
Surface Gravity: 9.798 m/s2
SoI Radius: 92 428 242 m
Atmospheric Characteristics
Atmospheric Height: 58 000 m
Scale Height: 8,435 m
Surface Pressure: 1.217 kg/m3
Surface Temperature: 288 K (14.85° C)
yes, you are correct
360/14=25.714285714 deg/h
8006034.718408/360*25.714285714=571859.6227371 meter/h
so the angular velocity is:
25.714285714/3600=0.0071428571428 deg/s
517859.6227371/3600=158.8498952 meter/s
Due to how degrees, arc minutes, and arc seconds work, 25.56 degrees per hour. So 25.56 arc seconds per second. Both of which are are roughly the droo 14 hour day. The true value is actually 25.71