Scientific Data

Some data for the cause:
the period of synchronous orbit is 14 hours, (as stated) and that orbit will occur at a height of ~8804.3 km (according to a reliable source)

Hey guys? Did you know that Droo is about the size of Mars? Yeah! SimpleRockets 2 is about half the scale of our solar system!

If only science was added to sr2

@MAHADI Cylero does have same orbital speed as Kerbin in KSP dho

let's go to Mars!

@Aerospacer thanks for finding error,I'll fix it

@PriyanshuRoy I am look to wiki.
Must be sqrt(2GM/r)

Sorry, never saw your post! I was hoping for some kind of community thread for everything about the game. If I get any mor new data I will post a comment here!

@jacksawild Your delta V may be slightly more accurate. I solved deltaV by using the rocket equation but alas I utilized the vacuum exhaust velocity for both atmospheric and orbital flight which will contribute some error. My method was manual reading of rocket masses at each stage using 8 different rockets all entering into a 115x115 then summing a total dV.

I'll try to put together a much more thorough experimental run at some point over the next few days.

The average atmospheric density between surface and 100km is about 5.21 PSI

@Aerospacer I used formula sqrt (GM/r)

@Rexy "I've been doing various test runs and delta V required to achieve LDO appears to be approximately 5.57 km/s"

Which way are you launching? Going east I can get 100km * 100km orbit with about 4.3km/s. Even less with an efficient design.

According to my totally scientific sample size of 1, the edge of Droo SOI is 95775.5km

P.S. Recalculate of escape velosity.
It's about 4997.4 m/s.
Zero-level orbital speed = 3533.7 m/s.

+1 interesting fact about Droo -
His average density ~27.5 t/m^3.
Sadly, the same mistake as in KSP - it's unrealistic...
(Osmium density ~22.6 t/m^3)

I've been doing various test runs and delta V required to achieve LDO appears to be approximately 5.57 km/s

Atmosphere air pressure can also be roughly approximated by the function:
p(h)=14.7exp(-(x/40000)^2)
units being PSI,

that was calculated experimentally taking engine thrust measurements every kilometer to look at dropoff, best fitting a gaussian packet, determining engine chamber pressure in vacuum, then solving for external air pressure as a function of altitude.

Also did some SCIENCE with Cylero and came up with this:
Radius: 678,000 m
Mass: 2.554717E+22 kg
Orbital Velocity at 150 km: 1435 m/s
Orbital Height above the Sun: 22,655 Mm
Escape Velocity: 2242.68 m/s

I got some info on Luna. Not sure how accurate it is, so I will probably update it soon, but here are some rough estimates:

Radius: 354,000 m
Mass: 3.00E+21 kg
Orbital Velocity at 30 km: 722.1 m/s
Orbital Height above Droo (Avg.): 37,200,500 m

@jacksawild You need more upvotes for your info

@DrCoconut1245
Earth mass is: 5.972 × 10^24 kg
radius is: 6.3781×10^6 m

So earth is about 5 times wider and 25 times more massive.

@jackawild Can we get comparisons to earth? The only thing I recognize is that the surface gravity is almost earths.

@PriyanshuRoy

M=ar^2/G

a = surface gravity = 9.798 m/s^2
r^2 = radius squared: 1274200^2 = 1623585640000 meters
G = gravity constant = 6.6726 x 10-11N-m^2/kg^2

So a bit more precise: 2.38406199992806×10^23kg, which alters droostationary height to 8803730 meters.

@jacksawild Thanks! But I didn't need to place a geostationary satellite.I just want to bring together the information.
PS how did you find mass of droo?

@PriyanshuRoy thanks

Good info. So to calculate geostationary altitude:

G = 6.67381x10^-11
M = 2.383561897×10^23 (mass of Droo)
t = 2540160000 (14 hours * 60 * 60)

cuberoot((6.67381x10^-11 * 2.383561897×10^23 * 2540160000) / 4* pi^2) = 10,077,834

Subtract radius of Droo (1274200 ) = 8803634.6 metres

About as close as I could get without RCS: https://youtu.be/GY3HpcblSpM

It has a period of 14hours and it seems to be sitting over the same continent. So I'd say it's pretty damn close.

Cool!