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    @SoulBlazer yes thanks, i think kinetic energy is important, mass and especially speed, but this is a torpedo, not a supersonic missile(
    thanks )

    +1 3.8 years ago
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    @Chtite451SR2 You probably misunderstood me (I'm from Russia, my English is not good), I did not increase the explosion damage in XML, I increased the "Detatcher force" parameter like this:
    from 2.5 (250%) to 250.5 (+ -20050%) (<Detacher force = "250.5" />)
    Thanks)

    +1 3.8 years ago
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    @Tweedle_Aerospace It's funny, only torpedo... but I found a method with a detatcher.. when the torpedo collides with the ship, detatcher triggers and pushes forward a half-ton tank with metalox, at the same time tank explodes. True, I had to change the detachment force in the code (XML), but the target-ship simply annihilates

    +1 3.8 years ago
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    @TritonAerospace I tried this but unfortunately it doesn't work, I did the experiment, the speed of the target is 180, and this returns about 330, but GoldenShadow made a working program that returns the correct value and vector soon

    2.2 years ago
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    @SamTheFox I would like to avoid copy/paste, but that seems to be the only way, thanks

    2.3 years ago
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    @SamTheFox hmm, thanks, but I meant to unload data outside the game, for example, to a text file; this function probably does not exist, but still I asked

    2.3 years ago
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    Hah, maybe "global engineering", a don't know, really:)
    I think Simple Rockets 2 is getting a bit more than a rocket game now. In my opinion, the game becomes a huge and interesting engineering sandbox where you can build and program not only rockets, but other surface vehicles, planes, etc. It's cool, I think if such a course is chosen, then the name of the game should reveal this (but maybe i'm wrong)

    2.3 years ago
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    @YaMomzBox420 Thank

    2.5 years ago
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    @plane918273645 Thank you very much, yes, I was able to translate the object coordinates from PCI into my own system, related to the part in a special way, but still interesting)

    2.5 years ago
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    @Tweedle_Aerospace unfortunately, not the kinetic energy... I came up with my own way, wrote the comments below, if i can take a picture in the comments..

    3.8 years ago